1852 United States presidential election in Tennessee

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United States presidential election in Tennessee, 1852

← 1848 November 2, 1852 1856 →
  Winfield Scott by Fredricks, 1862.jpg Franklin Pierce by Brady.jpg
Nominee Winfield Scott Franklin Pierce
Party Whig Democratic
Home state New Jersey New Hampshire
Running mate William A. Graham William R. King
Electoral vote 12 0
Popular vote 58,586 56,900
Percentage 50.73% 49.27%

President before election

Millard Fillmore

Elected President

Franklin Pierce

The 1852 United States presidential election in Tennessee took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for the Whig candidate, Winfield Scott, over Democratic candidate Franklin Pierce. Scott won Tennessee by a narrow margin of 1.46%.

Tennessee was one of the four states to vote for Scott in the 1852 election with the other three being Kentucky, Massachusetts and Vermont.

With 50.73% of the popular vote, Tennessee would prove to be Scott's second strongest state in the nation after Kentucky.[1]


United States presidential election in Tennessee, 1852[2][3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 58,586 50.73% 12 100.00%
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 56,900 49.27% 0 0.00%
Total 115,486 100.00% 12 100.00%


  1. ^ "1852 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1852 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 2 December 2017.
  3. ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.

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