United States presidential election in Tennessee, 1832

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United States presidential election in Tennessee, 1832

← 1828 November 2 – December 5, 1832 1836 →
  Andrew Jackson.jpg
Nominee Andrew Jackson
Party Democratic
Home state Tennessee
Running mate Martin Van Buren
Electoral vote 15
Popular vote 28,078
Percentage 95.42%

The 1832 United States presidential election in Tennessee took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for the Democratic Party candidate, state native Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Tennessee by a large margin of 90.84%.

Results

United States presidential election in Tennessee, 1832[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 28,078 95.42% 15
National Republican Henry Clay 1,347 4.58% 0
Totals 26,731 100.0% 15

References

  1. ^ "1832 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 12 April 2013. 
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