1892 United States presidential election in New Jersey

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United States presidential election in New Jersey, 1892

← 1888 November 8, 1892 1896 →
  StephenGroverCleveland.png Pach Brothers - Benjamin Harrison.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson Whitelaw Reid
Electoral vote 10 0
Popular vote 171,066 156,101
Percentage 50.67% 46.24%

President before election

Benjamin Harrison

Elected President

Grover Cleveland

The 1892 United States presidential election in New Jersey took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term, over Republican nominee, incumbent President Benjamin Harrison. Cleveland won his birth state by a narrow margin of 4.43%.


United States presidential election in New Jersey, 1892[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Adlai Ewing Stevenson I of Illinois 171,066 50.67% 10 100.00%
Republican Benjamin Harrison of Indiana Whitelaw Reid of New York 156,101 46.24% 0 0.00%
Prohibition John Bidwell of California James Cranfill of Texas 8,134 2.41% 0 0.00%
Socialist Labor Simon Wing of Massachusetts Charles Matchett of New York 1,337 0.40% 0 0.00%
People's James Baird Weaver of Iowa James Gaven Field of Virginia 985 0.29% 0 0.00%
Total 337,623 100.00% 10 100.00%


  1. ^ "1892 Presidential General Election Results – New Jersey". U.S. Election Atlas. Retrieved 23 December 2013.

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