United States presidential election in Michigan, 1840

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United States presidential election in Michigan, 1840

← 1836 October 30 - December 2, 1840 1844 →

  William Henry Harrison daguerreotype edit.jpg Martin Van Buren by Mathew Brady (cropped).jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 3 0
Popular vote 22,933 21,096
Percentage 51.71% 47.57%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in Michigan took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Michigan voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Michigan by a margin of 4.14%.

Results

United States presidential election in Michigan, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 22,933 51.71% 3 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 21,096 47.57% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 321 0.72% 0 0.00%
Total 44,350 100.00% 3 100.00%

References

  1. ^ "1840 Presidential General Election Results - Michigan". U.S. Election Atlas. Retrieved 23 December 2013. 
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