1836 United States presidential election in Louisiana

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United States presidential election in Louisiana, 1836

← 1832 November 3 – December 7, 1836 1840 →
  Van Buren.jpg HLWhite.jpg
Nominee Martin Van Buren Hugh White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard Johnson John Tyler
Electoral vote 5 0
Popular vote 3,842 3,583
Percentage 51.74% 48.26%

President before election

Andrew Jackson

Elected President

Martin Van Buren

The 1836 United States presidential election in Louisiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a margin of 3.48%.


United States presidential election in Louisiana, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 3,842 51.74% 5
Whig Hugh White 3,583 48.26% 0
Totals 7,425 100.0% 5


  1. ^ "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 4 August 2012.

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